Question
Obtain the values of : ${ }^{11} C_{4}$

Answer


$
\begin{aligned}
& { }^n \mathrm{C}_r=\frac{n !}{r !(n-r) !} \\
& \therefore{ }^{11} C_4=\frac{11 !}{41(11-4) !} \\
& =\frac{11 \times 10 \times 9 \times 8 \times 7 !}{4 \times 3 \times 2 \times 1 \times 7 !} \\
& =\frac{7920}{24}=330
\end{aligned}
$

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