Octane number has 0 value for - Vidyadip

MCQ

Octane number has $0$ value for

A
iso-octane
B
$n-$ hexane
✓
$n-$ heptane
D
iso-heptane

✓

Answer

Correct option: C.

$n-$ heptane

c
$n$-heptane is defined as the zero point of the octane rating scale. $2,2,4-$Trimethylpentane has an octane rating of $100$ , whereas $n$-heptane has an octane rating of $0$. The octane number is based on an arbitrary scale which is a measure of its ability to resist knocking, as it burns on combustion.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 9. Hydricarbon→9. Hydricarbon — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

$C- H$ bond type in benzene is :

For the redox reaction
$xP_4 + yHNO_3 \to H_3PO_4 + NO_2 + H_2O$

What is the weight of oxygen that is required for the complete combustion of $ 2.8 \,kg$ of ethylene? ....$kg$

Of the following pairs, the one containing example of metalloid elements in the periodic table is

The major product of the following reaction is

$C{H_3} - CH = C{H_2} + HBr\xrightarrow{{{{({C_6}{H_5}CO)}_2}{O_2}}}$

For the reaction : $N_2 (g)$ $+$ $3H_2(g)$ $\rightarrow$ $2NH_3(g)$, $\Delta H =\, -24\,Kcal$ at $427\,^oC$ and $200\,atm$ . Calculate magnitude of internal energy change (in $Kcal\,\Delta U$), if $168\,gm$ $N_2$ gas and $30 \,gm$ $H_2$ gas are allowed to react completely ( $100\%$ reaction yield) to form $NH_3$ gas at $427\,^oC$ and $200\,atm$......$Kcal$

Consider the following reaction

$C{O_{(g)}} + \frac{1}{2}{O_{2(g)}} \to C{O_{2(g)}}$

How are $\Delta E$ and $\Delta H$ releated for the reaction?

A hydrocarbon of formula ${C_6}{H_{10}}$ absorbs only one molecule of ${H_2}$ upon catalytic hydrogenation. Upon ozonolysis, the hydrocarbon yields $\begin{array}{*{20}{c}}
{\,H\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,H} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{O = C - C{H_2} - C{H_2} - C{H_2} - C{H_2} - C = O}
\end{array}$ The hydrocarbon is

The correct $IUPAC$ name of${H_2}C = CH - \mathop {\mathop {CH\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_2}C \equiv CH$

The rods of transition metals such as copper and zinc where potential difference is generated, are termed as :