MCQ
Of the following, non-existent compound is
- A$P{H_4}I$
- B$A{s_2}{O_3}$
- ✓$SbC{l_2}$
- D$A{s_2}{H_3}$
$V^{th}$ group elements normally show $+3$ and $+5$ oxidation state.
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$C{H_3} - C \equiv N\xrightarrow[{E{t_2}O}]{{C{H_3}Mgl}}\xrightarrow{{{H_3}{O^ \oplus }}}$
$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2} - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\
{\,\,OTs\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OTs}
\end{array}\xrightarrow[{(ii)\,KOH}]{{(i)\mathop {\,S}\limits^ \ominus H\,(one\,\,equivalent)}}[X]$
$[X]$ will be :
$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$
$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$
Based on the data given above, strongest oxidising agent will be :