MCQ
On heating $KCl{O_3}$, we get
- A$C{l_2}O$
- ✓$Cl{O_2}$
- C$Cl{O_3}$
- D$C{l_2}{O_7}$
✓
Answer
Correct option: B.
$Cl{O_2}$
b
(b) $3KCl{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\,\xrightarrow{\text{Heat}}\,$
(b) $3KCl{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\,\xrightarrow{\text{Heat}}\,$
$3KHS{{O}_{4}}+HCl{{O}_{4}}+2Cl{{O}_{2}}+{{H}_{2}}O$
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