- ✓Of common ion effect
- BThe solubility of $CdS$ is low
- C$C{d^{2 + }}$ions do not form complex with ${H_2}S$
- DThe solubility product of $CdS$ is low
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$\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_2}Cl}\limits_1 $ $\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_3}}\limits_2 $ $\mathop {\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C\mathop C\limits^ + {{(C{H_3})}_2}} \\
{|\,\,\,\,} \\
{Cl\,\,\,}
\end{array}}\limits_3 $ $\mathop {{{(C{H_3})}_2}\mathop C\limits^ + CH{{(C{H_3})}_2}}\limits_4 $
The pair $(s)$ of solutions which form a buffer upon mixing is(are)
$(A)$ $\mathrm{HNO}_3$ and $\mathrm{CH}_3 \mathrm{COOH}$
$(B)$ $\mathrm{KOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
$(C)$ $\mathrm{HNO}_3$ and $\mathrm{CH}_3 \mathrm{COONa}$
$(D)$ $\mathrm{CH}_3 \mathrm{COOH}$ and $\mathrm{CH}_3 \mathrm{COONa}$
$A$.$p$-xylene $B$.bromobenzene $C$.mesitylene $D$,nitrobenzene $E$.benzene
Choose the correct answer from the options given below.