MCQ
On the Celsius scale the absolute zero of temperature is at .......... $^oC$
- A$0$
- B$-32$
- C$100$
- ✓$-273.15$
✓
Answer
Correct option: D.
$-273.15$
d
(d) $T = 273.15 + t^\circ C$ $\Rightarrow$ $0 = 273.15 + t^\circ C$ $\Rightarrow$ $t = - 273.15^\circ C$
(d) $T = 273.15 + t^\circ C$ $\Rightarrow$ $0 = 273.15 + t^\circ C$ $\Rightarrow$ $t = - 273.15^\circ C$
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