MCQ
One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marked 4. Another die has one face marked 1 , two faces marked 2 , two faces marked 3 and one face marked 4. The probability of getting the sum of numbers to be 4 or 5 , when both the dice are thrown together, is
  • $\frac{1}{2}$
  • B
    $\frac{3}{5}$
  • C
    $\frac{2}{3}$
  • D
    $\frac{4}{9}$

Answer

Correct option: A.
$\frac{1}{2}$
(A
$a=$ number or dice 1
$b =$ number on dice 2
$
(a, b)=(1,3),(3,1),(2,2),(2,3),(3,2),(1,4),(4,1)
$
Required probability
$
\begin{array}{l}
=\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{1}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{2}{6}+\frac{1}{6} \times \frac{2}{6}+\frac{2}{6} \times \frac{1}{6}+\frac{1}{6} \times \frac{2}{6} \\
=\frac{18}{36}=\frac{1}{2}
\end{array}
$

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