One end of string of length $l$ is connected to a particle of mass $'m'$ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed $'v',$ the net force on the particle (directed towards centre) will be ($T$ represents the tension in the string)
A$T - \frac{{m{v^2}}}{l}$
B$0$
C$\;T\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;$
D$\;T + \frac{{m{v^2}}}{l}$
NEET 2017, Easy
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C$\;T\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;$
c Centripetal force $\frac{mv^2}{l}$ is provided by tension so net force on the particle will be equal to tension $T$
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