Consider a car moving along a straight horizontal road with a speed of $72\, km/h$. If the coefficient of kinetic friction between the tyres and the road is $0.5,$ the shortest distance in which the car can be stopped is ........ $m$ .$[g = 10\,m{s^{ - 2}}]$
AIPMT 1992, Medium
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(b)$s = \frac{{{u^2}}}{{2\mu \;g}} = \frac{{{{(20)}^2}}}{{2 \times 0.5 \times 10}} = 40\;m$
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