MCQ
One energy difference between the states $n = 2$ and $n = 3$ is $E \,eV$ in hydrogen atom. The ionization potential of $H$ atom is ........... $\mathrm{E}$
- A$3.2$
- B$5.6$
- ✓$7.2$
- D$13.2$
✓
Answer
Correct option: C.
$7.2$
c
${E_3} - {E_2} = E(eV)$ or $\frac{{ - {E_1}}}{9} + \frac{{{E_1}}}{4} = E$
${E_3} - {E_2} = E(eV)$ or $\frac{{ - {E_1}}}{9} + \frac{{{E_1}}}{4} = E$
$\therefore $ ${E_1} = \frac{{36E}}{5} = 7.2\,E$
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