One-forth length of a spring of force constant $K$ is cut away. The force constant of the remaining spring will be
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(b) By using $K \propto \frac{1}{l}$
Since one fourth length is cut away so remaining length is $\frac{3}{4}th$, hence $k$ becomes $\frac{4}{3}$ times i.e., $k' = \frac{4}{3}x$.
Since one fourth length is cut away so remaining length is $\frac{3}{4}th$, hence $k$ becomes $\frac{4}{3}$ times i.e., $k' = \frac{4}{3}x$.
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