One gm mol of a diatomic gas $(\gamma = 1.4)$ is compressed adiabatically so that its temperature rises from ${27^o}C$ to ${127^o}C$. The work done will be
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(a) $W = \frac{R}{{\gamma - 1}}({T_1} - {T_2})$
$ = \frac{{8.31 \times \{ (273 + 27) - (273 + 127)\} }}{{1.4 - 1}} = - 2077.5\;joules$
$ = \frac{{8.31 \times \{ (273 + 27) - (273 + 127)\} }}{{1.4 - 1}} = - 2077.5\;joules$
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