MCQ
One mole of a non-ideal gas undergoes a change of state ($2.0\, atm$, $3.0\, L$ , $95 \,K$ ) $\rightarrow $($4.0\, atm$ , $5.0\, L$ , $245\, K )$ with a change in internal energy, $\Delta U =30.0 \,L$ $atm$. The change in enthalpy $\Delta H$ of the process in $L\,atm$ is.
  • A
    $40.0$
  • B
    $42.3$
  • $44.0$
  • D
    Not defined because pressure is not constant

Answer

Correct option: C.
$44.0$
c
The change in the enthalpy is,

$\Delta H=H_{2}-H_{1}$

$=\left(U_{2}+P_{2} V_{2}\right)-\left(U_{1}+P_{1} V_{1}\right)$

$=\left(U_{2}-U_{1}\right)+\left(P_{2} V_{2}-P_{1} V_{1}\right)$

$=(30)-(40 \times 5-2 \times 3)$

$=44\, L\, atm$

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