Given : $\log 2=0.3, \ln 10=2.3$
$2 \rightarrow 3 \Rightarrow \text { Isochoric process }$
$3 \rightarrow 1 \Rightarrow \text { Isothermal process }$
$W = W _{1 \rightarrow 2}+ W _{2 \rightarrow 3}+ W _{3 \rightarrow 1}$
$=\left(- P \left( V _2- V _1\right)+0\left[- P _1 V _1 \ln \left(\frac{ V _2}{ V _1}\right)\right]\right)$
$=\left[-1 \times(40-20)+0+\left[-1 \times 20 \ln \left(\frac{20}{40}\right)\right]\right]$
$=-20+20 \ln 2$
$=-20+20 \times 2.3 \times 0.3$
$=-6.2 \text { bar } L$
$| W |=6.2 \text { bar } 1=620\,J$
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Assertion $A$ : Energy of $2 s$ orbital of hydrogen atom is greater than that of $2\,s$ orbital of lithium.
Reason $R$ : Energies of the orbitals in the same subshell decrease with increase in the atomic number.
In the light of the above statements, choose the correct answer from the options given below.