Step $1$ It is first compressed adiabatically from volume $V_{1}$ to $1 \;m ^{3}$.
Step $2$ Then expanded isothermally to volume $10 \;m ^{3}$.
Step $3$ Then expanded adiabatically to volume $V _{3}$.
Step $4$ Then compressed isothermally to volume $V_{1}$. If the efficiency of the above cycle is $3 / 4$, then $V_{1}$ is ............ $m^3$
$A B:$ Adiabatic compression,
$V_{A}=V_{1}, V_{B}=1 \,m ^{3}$
$B C:$ Isothermal expansion,
$V_{C}=V=10 \,m ^{3}$
$C D$ : Adiabatic expansion,
$V_{D}=V_{3}$
$D A$ : Isothermal compression,
$V_{A}=V_{1}$
Cycle efficiency is given, $\eta=\frac{3}{4}$
For given Carnot's cycle,
$\eta=1-\frac{T_{1}}{T_{2}}=1-\left(\frac{V_{2}}{V_{1}}\right)^{\gamma-1}$
$[\therefore$ Process $A B$ is adiabatic, $\gamma=\frac{5}{3}$ for monoatomic gas]
$\Rightarrow \quad \frac{3}{4}=1-\left(\frac{1}{V_{1}}\right)^{\frac{5}{3}-1} \Rightarrow \frac{1}{V_{1}^{2 / 3}}=\frac{1}{4}$
$\Rightarrow V_{1}=8 \,m ^{3}$
$1.$ efficiency more than $27 \%$
$2.$ efficiency less than the efficiency a Carnot engine operating between the same two temperatures.
$3.$ efficiency equal to $27 \%$
$4.$ efficiency less than $27 \%$

$(i)$ What is $W$ along path $ibf$ ?
$(ii)$ If $W = 13$ cal for path $fi$, what is $Q$ for the path $fi$ ?
$(iii)$ Take $E_{int,i} = 10\,\, cal$ then what is $E_{int,f}$ ?
