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An ideal gas is taken through a quasi-static process described by $P = \alpha\, V^2$, with $\alpha = 5\,atm/m^6$. The gas is expanded to twice its original volume of $1\,m^3$. How much work is done by the expanding gas in this process
Consider two containers $A$ and $B$ containing monoatomic gases at the same Pressure $(P)$, Volume $(V)$ and Temperature $(T)$. The gas in $A$ is compressed isothermally to $\frac{1}{8}$ of its original volume while the gas $B$ is compressed adiabatically to $\frac{1}{8}$ of its original volume. The ratio of final pressure of gas in $B$ to that of gas in $A$ is ...........
When an ideal triatomic non-linear gas is heated at constant pressure, the fraction of the heat energy supplied which increases the internal energy of the gas is
A perfect gas goes from state $A$ to another state $B$ by absorbing $8 \times {10^5}J$ of heat and doing $6.5 \times {10^5}J$ of external work. It is now transferred between the same two states in another process in which it absorbs ${10^5}J$ of heat. Then in the second process
Following figure shows on adiabatic cylindrical container of volume ${V_0}$ divided by an adiabatic smooth piston (area of cross-section = $A$ ) in two equal parts. An ideal gas $({C_P}/{C_V} = \gamma )$ is at pressure $P_1$ and temperature $T_1$ in left part and gas at pressure $P_2$ and temperature $T_2$ in right part. The piston is slowly displaced and released at a position where it can stay in equilibrium. The final pressure of the two parts will be (Suppose $ x$ = displacement of the piston)