MCQ
One mole of ${N_2}{H_4}$ loses $10\, mol$ of electrons to form a new compound $Y$. Assuming that all nitrogen appear in the new compound, what is the oxidation state of ${N_2}$ in $Y$ ? (There is no change in the oxidation state of hydrogen)
  • $+3$
  • B
    $-3$
  • C
    $-1$
  • D
    $+5$

Answer

Correct option: A.
$+3$
(a) $N_2^{ - 2}{H_4}$ $ \rightleftharpoons $ $\,2{N^{a + }} + 10{e^ - }$

$( - 2) \times 2 = 2a - 10$

$2a - [2 \times ( - 2)] = 10$

$a = + 3$.

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