MCQ
One of the configuration of n-butane is drawn in the given figure. Anticlockwise rotation of $C_2$ around $C_2-C_3$ bond by $120^o $ will lead to
- ✓gauche
- Bstaggerred
- Cpartially eclipsed
- Dfully eclipsed
✓
Answer
Correct option: A.
gauche
a
$C _2$ is rotated anticlockwise $120$ about $C _2- C _3$ bond.
$C _2$ is rotated anticlockwise $120$ about $C _2- C _3$ bond.
The resulting conformer is a Gauche conformer.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
When a strong acid, strong base or their salt are dissolved in water, they are completely ionised. If a strong acid is added to a strong base, ${H^ + }$ ions from the former combine with $O{H^ - }$ ions of the latter forming water. The formation of each water molecule liberates a certain quantity of energy and the reaction is exothermic. The heat liberated when one mole of water is formed by combining hydrochloric acid and sodium hydroxide is $ 13.7 \,kcal$. The heat liberated when one mole of water is formed by combining sulphuric acid and sodium hydroxide is......$kcal$
→At STP, what will be the volume of 2 gm methane?
Mechanical work is specially important in system that contain
Which of the following solutions are acidic?
When enthalpy and entropy change for a chemical reaction are $ - 2.5\, \times {10^3}\,cal$ and $7.4\,cal$ ${\deg ^{ - 1}}$ respectively. Predict the reaction at $298\,K$ is
→Assign $A, B, C, D$ from given type of reaction.
→A for disproportionation reaction.
B for comproportionation reaction.
C for either intermolecular redox reaction or displacement reaction.
D for either thermal combination redox reaction or thermal decomposition redox reaction.
$MnO_4^ - + {H^ + } + B{r^ - } \longrightarrow M{n^{2 + }}\left( {aq.} \right) + B{r_2} \uparrow $
Match List $I$ with List $II$
→| List-$I$ (Compound) | List-$II$ (Colour) |
| $A$ $\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O}$ | $I$ Violet |
| $B$ $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-}$ | $II$ Blood Red |
| $C$ $[\mathrm{Fe}(\mathrm{SCN})]^{2+}$ | $III$ Prussian Blue |
| $D$ $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3$ | $IV$ Yellow |
Choose the correct answer from the options given below :
$HClO$ is a weak acid. The concentration of ${H^ + }$ ions in $0.1\,M$ solution of $HClO\,({K_a} = 5 \times {10^{ - 8}})$ will be equal to
→Decreasing order of $C-C$ bond length is
→$I.$ ${C_2}{H_4}$ $II.$ ${C_2}{H_2}$
$III.$ ${C_6}{H_6}$ $IV.$ ${C_2}{H_6}$
The $pH$ of ${10^{ - 7}}M\,NaOH$ is
→