A bag $X$ contains $2$ white and $3$ black balls and another bag $Y$ contains $4$ white and $2$ black balls. One bag is selected at random and a ball is drawn from it. Then, the probability chosen to be white is,
  • A$\frac{2}{15}$
  • B$\frac{7}{15}$
  • C$\frac{8}{15}$
  • D$\frac{14}{15}$
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