A bag $X$ contains $2$ white and $3$ black balls and another bag $Y$ contains $4$ white and $2$ black balls. One bag is selected at random and a ball is drawn from it. Then, the probability chosen to be white is,
A$\frac{2}{15}$
B$\frac{7}{15}$
C$\frac{8}{15}$
D$\frac{14}{15}$
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D$\frac{14}{15}$
A white ball can be drawn in two mutually exclusive ways:
Selecting bag $X$ and then drawing a white ball from it.
Selecting bag $Y$ ane then drawing a white ball from it.
Let $E_1, E_2$ and $A$ be the three evenes as defined below:
$E_1 =$ Selecting bag $X$
$E_2 =$ Selecting bag $Y$
$A =$ Drawing a white ball
We know that one bag is selected randomly.
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