MCQ
Oxidation number of $N$ in $HN{O_3}$ is
- A$-3.5$
- B$+3.5$
- C$-3, +5$
- ✓$+5$
✓
Answer
Correct option: D.
$+5$
(d) $H\mathop N\limits^ * {O_3}$; $1 + x - 6 = 0$; $x = + 5$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
How much water is needed to dilute $10 \, ml$ of $10 \, N$ hydrochloric acid to make it exactly decinormal ($0.1\,N$) .......... $ml$
→Considering the above reactions, the compound $'A'$ and compound $'B'$ respectively are
→The complex(es), which can exhibit the type of isomerism shown by $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Br}_2\right]$, is(are) [en $=\mathrm{H}_2 \mathrm{NCH}_2 \mathrm{CH}_2 \mathrm{NH}_2$ ]
→($A$) $\left[\mathrm{Pt}(\mathrm{en})(\mathrm{SCN})_2\right]$
($B$) $\left[\mathrm{Zn}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$
($C$) $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_4\right]$
($D$) $\left[\mathrm{Cr}(\mathrm{en})_2\left(\mathrm{H}_2 \mathrm{O}\right)\left(\mathrm{SO}_4\right)\right]^{+}$
Product ; The Product is
Which of the following is correct ?
The equilibrium $PC{l_5}_{(g)\,}\, \rightleftharpoons \,PC{l_3}_{(g)} + \,C{l_{2(g)}}$ shows that $K_P\,(atm)$ is double to the value of $K_C$ $(mol/litre)$ at a particular temperature $T,$ then $T$ is ......$K$
→When solid potassium cyanide is added in water then
Arrange $S, P, As$ in order of increasing ionisation energy
→$12\,g$ of $Mg$ (at. mass $24$) will react completely with acid to give
→Major product $(R)$ of following reaction is
→Figure $\xrightarrow[{0\, - \,5\,\,{\,^o}C}]{{HN{O_2}}}$ $P$ $\xrightarrow{{HB{F_4}}}Q$ $\xrightarrow[{Cu,\,\,\Delta }]{{NaN{O_2}}}R$