MCQ
Oxidation number of osmium $(Os)$ in $Os{O_4}$ is
- A$+4$
- B$+6$
- C$+7$
- ✓$+8$
✓
Answer
Correct option: D.
$+8$
(d) $\mathop {Os\,{O_4}}\limits^{ * \,\,\,\,\,\,\,\,\,\,} $
$x + 4( - 2) = 0$
$x - 8 = 0$
$x = + 8$.
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