MCQ
Oxidation number of $S$ in $\mathrm{S}_2 \mathrm{O}_3{ }^{2-}$ is :
  • A
    $-2$
  • $+2$
  • C
    $+6$
  • D
    $0$

Answer

Correct option: B.
$+2$
Let Oxidation number of $S$ in $\mathrm{S}_2 \mathrm{O}_3{ }^{2-}$ be $x.$
Thus,
$2\text{x} + (-2 \times 3) = -2 $
$2\text{x} -6 = -2$
$2\text{x} = -2 + 6$
$2\text{x} = 4$
$\text{x}=\frac{4}{2}$
$\text{x}=2$
So the oxidation state of sulfur is $+2.$

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