MCQ
Oxidation state of iodine in $\mathrm{ICl}_2{ }^{-}$ is :
- ✓$+1$
- B$-1$
- C$+2$
- D$-2$
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To make it chiral compound the attack should be on which carbon atom
'$X$ ' and ' $Y$ ' respectively are :
$C + {O_2} \to C{O_2};\,\Delta H = - 394\,kJ\,mo{l^{ - 1}}$
$2CO + {O_2} \to 2C{O_2};\,\Delta H = - 569\,kJ\,mo{l^{ - 1}}$ The heat of formation of $1\,mol$ of carbon monoxide is thus .....$kJ\,mo{l^{ - 1}}$