MCQ
$P$ & $Q$ respectively is -


- A$DI-BALH$ followed by $H_2O$ and $Al(OCH_2CH_3)_3$
- B$LiAlH_4$ followed by $H_2O$ and

- ✓$DI-BALH$ followed by $H_2O$ and $m-CPBA$ followed by $C{H_3}OH/{H^ + }$
- DNone of these


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$MnO _{4}^{-}+8 H ^{+}+5 e ^{-} \rightarrow Mn ^{2+}+4 H _{2} O , E ^{\circ}=1.51 V$
The quantity of electricity required in Faraday to reduce five moles of $MnO _{4}^{-}$ is ..... .

Here $A$ is nothing but :