(p q) ( p q) is a

MCQ

$(p \wedge \sim q) \wedge(\sim p \wedge q)$ is a

A
Tautology
✓
Contradiction
C
Tautology and contradiction
D
Contingency

✓

Answer

Correct option: B.

Contradiction

(B) $(p \wedge \sim q) \wedge(\sim p \wedge q)$
$\equiv(p \wedge \sim p) \wedge(\sim q \wedge q) \ldots$...[Associative and commutative law]
$\equiv F \wedge F$...[Complement law]
$= F$
∴ Given statement is contradiction.

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