P_4 + 3NaOH + 3 H_2 O A + 3Na H_2 P O_2 here, 'A' is - Vidyadip

MCQ

${P_4} + 3NaOH + 3{H_2}O \to A + 3Na{H_2}P{O_2}$ here, $'A'$ is

A
$N{H_3}$
✓
$P{H_3}$
C
${H_3}P{O_4}$
D
${H_3}P{O_3}$

✓

Answer

Correct option: B.

$P{H_3}$

b
(b) This is the laboratory method of preparing phosphine gas.

${P_4} + 3NaOH + 3{H_2}O \to P{H_3} + 3Na{H_2}P{O_2}$

In this reaction, phosphorus disproportionate into phosphine and sodium hydrogen phosphite.

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