MCQ
Percentage of $s-$character in $s{p^3}$ hybrid orbital is
- ✓$25\%$
- B$50\%$
- C$66\%$
- D$75\%$
✓
Answer
Correct option: A.
$25\%$
(a) In $s{p^3}$ hybrid orbitals $s-$character is ${1/4}^{th}$ means $25\%.$
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