MCQ
Perdisulphuric acid has the following bond
- ✓$O\, \leftarrow \,O\,\, = \,\,O$
- B$ \leftarrow \,O\,\, = \,\,O \rightarrow $
- C$ > \,O \to \,O\, < $
- D$ - \,\,O\, - \,O\, - $
$H _2 O > H _2 S > H _2 Se > H _2 Te$
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$C{H_3}C{H_2}OH\xrightarrow{{P + {I_2}}}A\xrightarrow[{Ether}]{{Mg}}B $ $\xrightarrow{{HCHO}}C\xrightarrow{{{H_2}O}}D,$
then compound $'D'$ is -