MCQ
Perimeter of a rectangle whose length $( l )$ is $4 \ cm$ more than twice its breadth $(b)$ is $14 \ cm .$ The pair of linear equations representing the above information is
  • A
    $l+4=2 b$
    $2(l+b)=14$
  • B
    $l-b=4$
    $2(l+b)=14$
  • C
    $l=2 b+4$
    $l+ b =14$
  • $l=2 b+4$
    $2(l+b)=14$

Answer

Correct option: D.
$l=2 b+4$
$2(l+b)=14$
$l=2 b+4$
$2(l+b)=14$
To solve the above question,
let us break the statement into parts.
It says that perimeter is $14 \ cm$
$\therefore 2(1+b)=14$
Also, length is $4 \ cm$ more than twice its breadth.
$\Rightarrow \text { Length }=2 \times \text { Breadth }+4$
$\therefore l=2 b+4$

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