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$Ph - CH _{2}- CH = CH - CH _{3}$ $\xrightarrow[{{\text{(ii) }}Alc.\,KOH}]{{{\text{(i) B}}{{\text{r}}_2}}}$

• A
  $Ph - CH = CH - CH = CH _{2}$
• B
  $\begin{array}{*{20}{c}}
    {Ph - C{H_2} - CH - CH - C{H_3}} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,} \\ 
    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,OH\,\,\,} 
  \end{array}$
• ✓
  $Ph - CH _{2}- C \equiv C - CH _{3}$
• D
  $Ph - C \equiv C - CH _{2}- CH _{3}$