- ✓${\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]^ + }$
- B$A{g_2}O$
- C${\left[ {Cu{{\left( {OH} \right)}_4}} \right]^{2 - }}$
- D$C{u_2}O$
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$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C{H_2} - C - C{H_2} - C{H_2}}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C{H_2} - C{H_2} - C - N{H_2}}
\end{array}$
$E_{\frac{1}{2}Cl_2/Cl^- }^o = 1.36\,V\,,\,E_{C{r^{3 + }}/Cr}^o = - 0.74\,V$
$E_{C{r_2}O_7^{2 - }/C{r^{3 + }}}^o = 1.33\,V\,,\,E_{MnO_4^ - /M{n^{2 + }}}^o = 1.51\,V$
The correct order of reducing power of the species $(Cr, Cr^{3+}, Mn^{2+}$ and $Cl^-)$ will be
$I.$ $1$ molecule of oxygen
$II.$ $1$ atom of nitrogen
$III.$ $1 \times {10^{ - 10}}$ $g$ molecular weight of oxygen
$IV.$ $1 \times {10^{ - 10}}$ $g$ atomic weight of copper