MCQ
$P{H_4}I + NaOH$ forms
- ✓$P{H_3}$
- B$N{H_3}$
- C${P_4}{O_6}$
- D${P_4}{O_{10}}$
$PH _4 I + NaOH \rightarrow PH _3+ H _2 O + NaI$
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$[(\eta^5 - C_5H_5) Fe(CO)_2Cl]$ is
(Molecular mass of $CHCl_3 = 119.5 \,u$ and molecular mass of $CH_2Cl_2 = 85\, u$)