MCQ
Point (- 10,0) lies
- Aon the negative direction of the y-axis
- Bon the negative direction of the X-axis
- Cin the third quadrant
- Din the fourth quadrant
✓
Answer
(b) on the negative direction of the X-axis
Explanation: In point (-10, 0) y-coordinate is zero, so it lies on X-axis and its x-coordinate is negative, so the point (-10, 0) lies on the X-axis in the negative direction.
Explanation: In point (-10, 0) y-coordinate is zero, so it lies on X-axis and its x-coordinate is negative, so the point (-10, 0) lies on the X-axis in the negative direction.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A $(-6,3)$ be a point on the graph. Draw $A L \perp x-$ axis. The co-ordinates of L are
→E Divides $AB$ in the ratio $1 : 3$ and also, $F$ divides $AC$ in the ratio $1 : 3. EF = 2.8\ cm$, Find $BC =?$
→Let $m$ be the mid-point and $l$ be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is:
→A line segment, when extended indefinitely in one direction is called $a:$
→A grouped frequency distribution table with classes of equal sizes using $63-72 (72$ included$)$ as one of the class is constructed for the following data $30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, 40, 14, 20, 15, 35, 44, 66, 75, 84, 95, 96, 102, 110, 88, 74, 112, 14, 34, 44.$ How many classes can we have$?$
→In the adjoining figure, $AB = BC$ and $\angle ABD =\angle CBD$, then another angle which measures $30^{\circ}$ is
→If $\text{x}+\frac{1}{\text{x}}=3,$ than the value of $\text{x}^2+\frac{1}{\text{x}^2}$ is:
→$(x+y)^3-(x-y)^3$ can be factorized as:
→Each angle of an equilateral triangle is:
In the following, write the correct answer.Two sides of a triangle are of lengths $5\ cm$ and $1.5\ cm$. The length of the third side of the triangle cannot be:
→