Position of a body with acceleration 'a' is given by x = K{a^m}{t^n}, here t is time. Find dimension of m and n.

Q: Position of a body with acceleration '$a$' is given by $x = K{a^m}{t^n},$ here $t$ is time. Find dimension of $m$ and $n$.

b (b) As $x = K{a^m} \times {t^n}$ $\left[ {{M^0}L{T^0}} \right] = {\left[ {L{T^{ - 2}}} \right]^m}{\left[ T \right]^n} = \left[ {{L^m}{T^{ - 2m + n}}} \right]$ $\therefore $ $m = 1$ and $ - 2m + n = 0$ $⇒$ $n = 2$.

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

Position of a body with acceleration '$a$' is given by $x = K{a^m}{t^n},$ here $t$ is time. Find dimension of $m$ and $n$.

A$m = 1$, $n = 1$
B$m = 1,\;n = 2$
C$m = 2,\;n = 1$
D$m = 2,\;n = 2$

Medium

STD 11 Science
JEE
STD 11 - 1. units,dimensions and measurement
Physics

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