MCQ
Potassium dichromate acts as a strong oxidizing agent in acidic solution. During this process, the oxidation state changes from
- A$+3$ to $+1$
- ✓$+6$ to $+3$
- C$+2$ to $+1$
- D$+6$ to $+2$

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List - $I$ | List - $II$ |
| $ICI$ | $\mathrm{T}$-Shape |
| $\mathrm{ICI}_3$ | Square pyramidal |
| $\mathrm{CIF}_5$ | Pentagonal bipyramidal |
| $\mathrm{IF}_7$ | Linear |
Choose the correct answer from the options given below: