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Potential difference $(\triangle\text{V})$ between two points A and B separated by a distance x, in a uniform electric field E is given by $\triangle\text{V}=-\text{Ex},$ where xis measured parallel to the field lines. If a charge q₀ moves from P to Q, the change in potential energy $(\triangle\text{U})$ is given as $\triangle\text{U}=-\text{q}_0\triangle\text{V}.$ A proton is released from rest in uniform electric field of magnitude 4.0 × 10⁸Vm^-1 directed along the positive X-axis. The proton undergoes a displacement of 0.25m in the direction of E.

Mass of a proton = 1.66 × 10^-27kg and charge of proton = 1.6 × 10^-19C.

1. The change in electric potential of the proton between the points A and B is:

1. -1 × 10⁸V
2. 1 × 10⁸V
3. 6.4 × 10^-19V
4. -6.4 × 10^-19V

2. The change in electric potential energy of the proton for displacement from A to B is:

1. 1.6 × 10¹¹J
2. 0.5 × 10²³J
3. -1.6 × 10^-11J
4. 3.2 × 10²²J

3. The mutual electrostatic potential energy between two protons which are at a distance of 9 × 10^-15m, in ₉₂U²³⁵ nucleus is:

1. 1.56 × 10^-14J
2. 5.5 × 10^-14J
3. 2.56 × 10^-14J
4. 4.56 × 10^-14J

4. If a system consistsoftwocharges 4mC and -3mC with no external field placed at (-5cm, 0, 0) and (5cm, 0, 0) respectively. The amount of work required to separate the two charges infinitely away from each other is:

1. -1.1J
2. 2J
3. 2.5J
4. 3J

5. As the proton moves from P to Q, then:

1. The potential energy of proton decreases.
2. The potential energy of proton increases.
3. The proton loses kinetic energy.
4. Total energy of the proton increases.