MCQ
Predict the formula of a compound formed between a metal $'M\ '$ which has $1^{st}, 2^{nd}, 3^{rd}\ \ce{IP}$ values as $518, 7314, 9820KJ$ mol $^{-1}$ respectively and a halogen $'X\ '.$
  • A
    $\ce{MX_2}$
  • B
    $\ce{M_2vX_3}$
  • C
    $\ce{MX_3}$
  • $\ce{MX}$

Answer

Correct option: D.
$\ce{MX}$
Alkali metals have low first ionization energies and relatively higher second and third ionization energies because the electron have to be remover from a stable octet.
As in the given question, there is more difference in the values of first and second ionization energies i.e. the metal has $1$ valence electron,
$\therefore$ formula of the compound will be $\ce{MX}.$

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