- A

- ✓

- C

- D






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$CO\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \rightleftharpoons C{O_2}\left( g \right)$ is
(given, $\frac{ F }{ R }=11500 K V ^{-1}$, where $F$ is the Faraday constant and $R$ is the gas constant, The value of $\ln (10)=2.30$ )
Statement $I$ : Sulphanilic acid gives esterification test for carboxyl group.
Statement $II$ : Sulphanilic acid gives red colour in Lassigne's test for extra element detection.
In the light of the above statements, choose the most appropriate answer from the options given below :
$C{H_2} = C{H_2}\xrightarrow{{HBr}}X\xrightarrow{{{\text{Hydrolysis}}}}Y\mathop {\xrightarrow{{N{a_2}C{O_3}}}}\limits_{{I_2}{\text{ excess}}} Z$