MCQ
Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is
- ✓$8:1$
- B$0.8:1$
- C$2:1$
- D$4:1$
✓
Answer
Correct option: A.
$8:1$
a
$\Delta P _{1}=0.01=4 T / R _{1} \quad \ldots . .(1)$
$\Delta P _{1}=0.01=4 T / R _{1} \quad \ldots . .(1)$
$\Delta P _{2}=0.02=4 T / R _{2} \quad \ldots . .(2)$
Equation $(1)+(2)$
$\frac{1}{2}=\frac{ R _{2}}{ R _{1}}$
$R _{1}=2 R _{2}$
$\frac{V_{1}}{V_{2}}=\frac{R_{1}^{3}}{R_{2}^{3}}=\frac{8 R_{2}^{3}}{R_{2}^{3}}=8$
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