MCQ
Pressure inside two soap bubbles are $1.02 \,atm$ and $1.05 \,atm$ respectively. The ratio of their surface area is .........
- A$\frac{125}{8}$
- ✓$\frac{25}{4}$
- C$\frac{5}{2}$
- D$\frac{2}{5}$
Excess pressure $\Delta P =\frac{4 T }{ R }$
$\frac{\Delta P _1}{\Delta P _2}=\frac{ R _2}{ R _1}=\frac{2}{5}$
$\frac{ S _1}{ S _2}=\left(\frac{ R _2}{ R _1}\right)^2=\frac{25}{4}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

