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Thermodynamics — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsThermodynamics1 Mark
MCQ
Pressure-temperature relationship for an ideal gas undergoing adiabatic change is $\left(\gamma=C_p / C_v\right)$
  • A
    $P T^\gamma=$ constant
  • B
    $P T^{-1+\gamma}=$ constant
  • C
    $P^{\gamma-1} T^\gamma=$ constant
  • ✓
    $P^{1-\gamma} T^\gamma=$ constant
✓

Answer

Correct option: D.
$P^{1-\gamma} T^\gamma=$ constant
(d)$PV^\gamma=\text{constant}$
$\Rightarrow P\left(\frac{RT}{P}\right)^\gamma=\text { constant } $
$\Rightarrow P^{1-\gamma} T^\gamma=\text { constant. }$

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