$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$
કાર્બન્સ $1, 3$ અને $5$ ના સંકરણની સ્થિતિ નીચેના ક્રમમાં છે, તો સાચો ક્રમ શોધો.
${\left( {C{H_3}} \right)_3}C - CH = C{H_2}\xrightarrow[{\left( {ii} \right)\,NaB{H_4} + NaOH}]{{\left( i \right)\,Hg{{\left( {C{H_3}COO} \right)}_2};\,THF}}\,?$
$C{{H}_{3}}CH\,=\,\,C{{H}_{2}}\,+\,\,{{H}_{2}}O\,\,+\,\,[O]\,\,\underset{Acid}{\mathop{\xrightarrow{KMn{{O}_{4}}}}}\,$$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,OH\,\,\,\,\,\,\,OH}
\end{array}$ $\xrightarrow{{[O]}}{\mkern 1mu} {\mkern 1mu} X{\mkern 1mu} {\mkern 1mu} + {\mkern 1mu} {\mkern 1mu} HCOOH$
$X$ શું છે ?