a $\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{Hl} \stackrel{373 \,K}{\longrightarrow} \mathrm{H}_{3} \mathrm{Cl}+\left(\mathrm{CH}_{3}\right) \mathrm{CHOH}$
In the case of unsymmetrical ether, the alkyl halide is always formed from a smaller alkyl group. This happens so because $I^-$ ion being larger in size approaches smaller alkyl group to avoid steric hindrance.
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