સંતુલને $|P|=|R|$
$\therefore x-a=4 a$
$\therefore x=5 a$
$\therefore|P|=x-a=4 a$
$\quad|Q|=x-3 a=2 a$
$K_{c}=\frac{(4 a)^2}{4 a \times(2 a)^3}=\frac{4 \times 4 \times 4 \times 4}{4 \times 2 \times 2 \times 2}=8$
$400\, K$ $\Delta G ^{\circ}=+25.2\, kJ mol ^{-1}$. એ $2 A ( g ) \rightleftharpoons A _{2}( g )$
આ પ્રકિયા માટે સંતુલન અચળાંક $K _{ C }$$...... \times 10^{-2}$
$\left.\log _{10} 2=0.30,1\, atm =1\, bar \right]$
$[$ antilog $(-0.3)=0.501]$