$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
પ્રકિયા ની પદ્ધતિ $(i)$ અને $(ii)$ અનુક્રમે શું હશે ?
$(1)$ $C{H_3}C{H_2}C{H_2}Cl + $ $\begin{array}{*{20}{c}}
{\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,|}
\end{array}} \\
{C{H_3} - C - {O^ - }} \\
{\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ $(2)$ $C{H_3}C{H_2}C{H_2}I + $$\begin{array}{*{20}{c}}
{\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,|}
\end{array}} \\
{C{H_3} - C - {O^ - }} \\
{\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(3)$ $\begin{array}{*{20}{c}}
{{H_3}C - CH - C{H_3}} \\
{|\,\,\,\,} \\
{Br\,\,\,}
\end{array}$ $+CH_3O^-$ $(4)$ $\begin{array}{*{20}{c}}
{{H_3}C - CH - C{H_3}} \\
{|\,\,\,\,} \\
{Br\,\,\,}
\end{array}$ $+CH_3S^-$



$n - Pr = n -$ propyl
નીપજ ' $(A)$ શું હશે ?

