$(I)\,\,CH_3CH_2OH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$
$(II)\,\,CH_3CH_2OH + HCl \rightarrow$
$(III)\,\,(CH_3)_3COH + HCl \rightarrow$
$(IV)\,\,(CH_3)_2CHOH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$