$C{H_3}Cl\,\,\xrightarrow{{KCN}}\,\,(A)\,\,\xrightarrow{{{H_2}{O^ + }}}\,\,(B)\,\,\xrightarrow{{N{H_3}}}\,\,(C)\,\,\xrightarrow{\Delta }\,\,(D)$
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CHC{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,H\,\,\,\,\,\,\,Br}
\end{array}$ $\xrightarrow{{C{H_3}OH}}$
$\begin{align}
(A)\,Nu+R-L\to \overset{\oplus }{\mathop{Nu}}\,-R+{{L}^{-}} \\
(B)\,R-{{L}^{\oplus }}\to {{R}^{\oplus }}+:L \\
\end{align}$
$(I)\,\begin{array}{*{20}{c}}
{C{H_3}CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)\,CH_3CH_2CH_2Cl$
$(III)\,H_3CO-C_6H_4-CH_2Cl$