MCQ
Probability is 0.45 that a dealer will sell at least 20 television sets during a day, and the probability is 0.74 that he will sell less that 24 televisions. The probability that he will sell 20, 21, 22 or 23 televisions during the day, is:
  • 0.19
  • B
    0.32
  • C
    0.21
  • D
    None of these

Answer

Correct option: A.
0.19
Let A be the event that the sale is at least 20 televisions, i.e. 20, 21, 22,... and B be the event that sale is less than 24 i.e. 0.1.2.3...23.
Then A∩B will denote the sale of 20, 21, 22 and 23 televisions, We are given P(A) = 0.45 and P(B) = 0.74.
It is required to find P(A ∩ B).
Also P(A ∪ B) = P( sale of 0, 1, 2, 3,...,20, 21, 22, 23 televisions) = P(S) = 1.
From addition rule, required probability is P(A ∩ B) = P(A) + P(B) - P(A ∪ B) = 0.45 + 0.74 - 1 = 0.19.

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