MCQ
Product $A$ is


- A

- B

- C

- ✓







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| Column $-I$ | Column $-II$ |
| $(a)$ $4s$ | $(p)$ Circular orbit around nucleus |
| $(b)$ $4p$ | $(q)$ Non directional orbital |
| $(c)$ $1s$ | $(r)$ Angular momentum $=2h/\pi $ |
| $(d)$ $3d$ | $(s)$ Radial node is zero |
$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.