MCQ
Product $(C)$ of the above reaction is


- A

- ✓

- C

- D








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$C{H_3} - C{H_2} - Br\,\xrightarrow{{KCN}}\,\xrightarrow[{{H_2}O}]{{\bar OH}}\,\xrightarrow[\Delta ]{{PC{l_5}}}$ product